The amplitude of body vibrations on the spring is 1 dm, the frequency is 100 Hz. What path will the point cover in 0.2 min?
| September 17, 2021 | education
0.2 minutes = 60 s * 0.2 = 12 s.
The number of oscillations n during a time t with a frequency v:
n = νt.
Path of point s in one swing:
s = 4A, where A is the amplitude.
Path of point S in time t:
S = ns = 4νtA = 4 * 100 Hz * 12 s * 0.1 m = 480 m.
Answer: 480 m.
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