The amplitude of the body oscillation is 0.25 m. What is the displacement of the body in a time

The amplitude of the body oscillation is 0.25 m. What is the displacement of the body in a time equal to two oscillation periods?

Answer: in. 2m
Since in one full period of oscillation the body travels a path that can be expressed as a fourfold maximum deviation of this body from its equilibrium point (or counting from the beginning of the movement until the moment the body returns to the starting point, which has completed a full oscillation), then in a time equal to two periods of oscillation, the path traversed by the body can be expressed as: s = 4 * A * 2, where A is the amplitude of the oscillation.

Thus, the path will be: s = 4 * 0.25 * 2 = 2m.