The angle A of triangle ABC is 40 degrees, and the outside angle with vertex B is 105 degrees. Find corner C.

The external angle ABC and the internal angle ABC of the triangle ABC are adjacent angles, the sum of which is 180, then the angle ABC = 180 – AED = 180 – 105 = 75.

The sum of the inner angles of the triangle is 180, then the angle ACB – 180 – CAB – ABC = 180 – 40 – 75 = 65.

Answer: The ACB angle is 65.



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