The angle at the apex of an isosceles triangle is 30 degrees

The angle at the apex of an isosceles triangle is 30 degrees; the height is lowered to the lateral side. find the angle between this height and the base.

According to the condition, the triangle ABC is isosceles, then the angles at the base of the AC are equal.

Angle BAC = BCA = (180 – ABC) / 2 = (180 – 30) / 2 = 150/2 = 75.

The height AH forms a right-angled triangle AНС, the sum of the inner angles of which is 180. Then the angle CAН = (180 – BCA – AНС) = (180 – 75 – 90) = 15.

Answer: The angle between height and base is 15.



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