The angle at the apex of an isosceles triangle is 80, which is the angle between the height drawn to the side and the base

Since the triangle ABC is isosceles, the angle BAC = BCA = (180 – ABC) / 2 = (180 – 84) / 2 = 48.

In a right-angled triangle AСН, the angle is AСН = 180 – AНС – BAC = 180 – 90 – 48 = 42.

Answer: The angle between height and base is 42.



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