The angle at the base of an isosceles triangle is 30. Determine the angle between the lateral

The angle at the base of an isosceles triangle is 30. Determine the angle between the lateral side and the height lowered to the other side.

Determine the angle at the vertex B of the triangle ABC.

Angle ABC = 180 – 30 – 30 = 120.

The СВН angle is adjacent to the ABC angle, then the СВН angle = 180 – 120 = 60.

In a right-angled triangle СВН, the angle BCH = 180 – 90 – 60 = 30.

Answer: The angle between the side and the height is 30.



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