The angle at the base of an isosceles triangle is 50 degrees. find the angle between one side

The angle at the base of an isosceles triangle is 50 degrees. find the angle between one side and the height lowered to the other side.

Since the angles at the base of an isosceles triangle are equal to each other, and the sum of the angles of any triangle is 180 °, we can find the angle at the vertex of this triangle:

180 ° – 50 ° – 50 ° = 80 °.

Lowering the height from the corner at the base to the opposite side to it, we get a right-angled triangle, one of the acute angles of which is equal to the angle at the apex of this isosceles triangle. The second acute angle of the resulting right-angled triangle is the desired angle between the lateral side and the height. Its value is 180 ° – 90 ° – 80 ° = 10 °.