The angle between the bisector of a given angle and a ray complementary to one of its sides is 134 °. Find the given corner.

<AOС is divided by the sectrix ОВ into 2 equal angles <AOB and <BOS
Beam OA1 an additional beam OA is made with a sectrix OC <A1OB = 134 °
<AOA1 = 180 ° (unfolded)
<AOA1 = <A1OB + <AOB
<AOB = 180 ° -134 ° = 46 ° – half the angle AOC
<AOC = 46 • 2 = 92 °
Answer = 92 °



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