The angle between the diagonals of the rectangle is 60 ° and the smaller side is 4cm. Find the diagonal of the rectangle.

Consider a triangle AOB, whose side OA = OB, as half of the diagonals, which are halved at the intersection, angle O = 60, side AB = 4 cm.

If in an isosceles triangle at least one angle is equal to 600, then this triangle is equilateral.

Then AB = AO = BO = 4 cm.

Diagonals AB = BC = 2 * AO = 2 * 4 = 8 cm.

Answer: The length of the diagonals of the rectangle is 8 cm.



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