The angle between the diagonals of the rectangle is 80 degrees. find the corners between the diagonal of the rectangle and it.

The diagonals of a rectangle divide it into isosceles triangles, and opposite triangles are equal.

In an isosceles triangle, the angles at the base are equal, then:

The angle OAB = OBA = OCD = ODC, as well as the angle ODA = OAD = OCB = OBC.

Angle ОАВ = (180 – 80) / 2 = 50.

Then the angle OAD = 90 – 50 = 40.

Answer: The angles between the diagonals and the sides are 40 and 50.



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