The angle between the two heights of the rhombus drawn from the top of the obtuse angle is 56 °

The angle between the two heights of the rhombus drawn from the top of the obtuse angle is 56 ° Find the value of the acute angle of the rhombus.

Consider a quadrangle ВНDK formed by the heights of ВН and ВK.

The sum of the inner angles of the quadrangle is 360, then the angle НDК = (360 – НВК – ВНD – BKD) = (360 – 56 – 90 – 90) = 124.

Since the rhombus has a sum of adjacent angles equal to 180, the angle ABD = (180 – ADC) = (180 – 124) = 56.

Answer: The acute angle of the rhombus is 56.



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