The angle between the two radii is: 52 degrees. Find the angle between the tangents drawn through the ends of these radii.

By the property of the tangent, the radius of the circle drawn to the point of tangency forms an angle with this tangent, then the angle ОВС = ОАС = 90.
Consider a quadrangle ОАСВ in which the angle АВ, by condition, is equal to 52, the angles ОАС and ОВС are straight, and the sum of internal angles is 360.
Then the angle ACB = (360 – ОАВ – ОАС – ОВС) = (360 – 52 – 90 – 90) = 128.
Answer: The angle between tangents is 128.