The angle is 60 degrees, the sides of the angle are 4 cm, you need to calculate the distance between

The angle is 60 degrees, the sides of the angle are 4 cm, you need to calculate the distance between the extreme points of the angle.

Let’s draw the angle ABC, and which angle B is 60, and the segments AB and CB are 4 cm.

You will get an isosceles triangle ABC with one of the angles 60.

If there is at least one angle 60 in an isosceles triangle, then such a triangle is equilateral. Then AC = AB = CB = 4 cm.

Answer: The distance between the extreme points of the corner is 4 cm.



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