The angles of the rhombus add up to 120 degrees. Find the corners of the diamond.

Let ABCD be a rhombus. Since the opposite angles of the rhombus are equal, then angle A = angle C, angle B = angle D.
1. By condition given:
angle A + angle C = 120 degrees.
Let’s denote angle A and angle C as x, then:
x + x + = 120;
2x = 120;
x = 120/2;
x = 60.
Angle A = angle C = 60 degrees.
2. By the theorem on the sum of the angles of a quadrangle:
angle A + angle B + angle C + angle D = 360 degrees.
Substitute the known values:
60 + angle B + 60 + angle D = 360;
angle B + angle D = 360 – 120;
angle B + angle D = 240.
Since angle B = angle D, we denote them as y:
y + y = 240;
2y = 240;
y = 240/2;
y = 120.
Angle B = Angle D = 120 degrees.
Answer: angle A = 60 degrees, angle B = 120 degrees, angle C = 60 degrees, angle D = 120 degrees.