The angular speed of a shaft with a radius of 5 cm is equal to 31.4 rad / s. Determine the linear speed

The angular speed of a shaft with a radius of 5 cm is equal to 31.4 rad / s. Determine the linear speed of points on the surface of the shaft, the period and frequency of rotation.

Given:

R = 5 centimeters = 0.05 meters – shaft radius;

pi = 3.14 – geometric constant;

W = 31.4 rad / second – the angular velocity of the shaft.

It is required to determine the linear speed of a point on the surface of the shaft U, the period of rotation of the shaft T and the frequency of rotation of the shaft n.

U = R * W = 0.05 * 31.4 = 1.57 m / s.

T = 2 * pi / W = 2 * 3.14 / 31.4 = 2 * 0.1 = 0.2 s ^ -1.

n = 1 / T = 1 / 0.2 = 5 revolutions per second.

Answer: the linear speed is 1.57 meters per second, the rotation period is 0.2 1 / second, the rotation frequency is 5 revolutions per second.