The apple fell from a 6 m high tree. How long does it take for the apple to fall to the ground.

The apple fell from a 6 m high tree. How long does it take for the apple to fall to the ground. What is the speed during the fall?

h = 6 m.

g = 10 m / s2.

V0 = 0 m / s.

t -?

V -?

When an apple falls, only gravity acts on it, so the apple moves with the acceleration of gravity g.

The height of the fall of the apple h can be expressed by the formula: h = V0 * t + g * t ^ 2 / 2. Since the apple falls from a state of rest V0 = 0 m / s, the formula will take the form: h = g * t ^ 2/2 …

t = √ (2 * h / g).

t = √ (2 * 6 m / 10 m / s2) = 1.1 s.

g = (V – V0) / t.

V – V0 = g * t.

V = V0 + g * t.

V = 0 m / s + 10 m / s2 * 1.1 s = 11 m / s.

Answer: the apple will fall for a time t = 1.1 s and, when hitting the ground, it will have a speed of V = 11 m / s.