The aquarium is in the shape of a rectangular parallelepiped and contains 0.2 m3 of water. How much pressure does this water

The aquarium is in the shape of a rectangular parallelepiped and contains 0.2 m3 of water. How much pressure does this water exert on the bottom of the aquarium? Bottom area 0.5 m2.

Let’s calculate the height of the liquid in the aquarium:

h = V / S = 0.2 / 0.5 = 0.4 (m);

The pressure of the liquid column is calculated by the formula:

p = d * g * h, where d is the density of the liquid, kg / m3, g is the acceleration of gravity, h is the height of the liquid column.

d (H2O) = 1000 kg / m3

p = 1000 * 9.8 * 0.4 = 3920 Pa.

Answer: 3920 Pa.