The archer shoots the arrow vertically upward with an initial speed of 20m / s to what maximum height it can rise.

Task data: V (initial speed of the considered boom) = 20 m / s.

Reference values: g (acceleration due to gravity) ≈ 10 m / s2.

The maximum lifting height of the considered boom is determined from the equality (we apply the law of conservation of energy): En = Ek and m * g * h = m * V ^ 2/2, whence h = m * V ^ 2 / (2 * m * g) = V ^ 2 / (2 * g).

Let’s perform the calculation: h = 20 ^ 2 / (2 * 10) = 20 m.

Answer: The maximum lifting height of the boom in question is 20 m.