The area of a parallelogram, the adjacent sides of which are 4 cm and 7 cm, is 7 cm ^ 2. Find its height and acute angle.

We are given a parallelogram ABCD AB = 4 AD = 7 The area of the parallelogram S = ah (where a is the side to which the height is drawn, in our case it is the height BH drawn from the top B to the base AD) 7 = a * 7 a = 1 = BH height BH received a right-angled triangle ABH, in which we know 2 sides and an angle By the theorem of sines we can find the angle BAH sinA = 1/4 angle A (Acute angle of a parallelogram) = arksin 1/4