The area of a rectangle is 4225dm squared. Its width is 6m5dm. Find the area of another rectangle

The area of a rectangle is 4225dm squared. Its width is 6m5dm. Find the area of another rectangle, the width of which is thirteenth of the length of the first, and the length is a fifth of the length of the first rectangle.

Find the length of the first rectangle, provided that its width = 6 m 5 dm (65 dm), and the area is 4225 dm².
If S = a * b. Therefore, the first factor is the quotient of the second:

a = S: b = 4225: 65 = 65 dm. Since all sides are equal, most likely – this quadrilateral is a square.

The width of another similar figure is 1/13 of the length of the previous one.
In order to find the part of an integer value, you must divide it by the denominator of the fraction and multiply by its numerator.

65: 13 * 1 = 5 dm.

Length = 1/5:

65: 5 * 1 = 13 dm.

Let’s calculate the area:
S = 13 * 5 = 65 md².