The area of an acute-angled triangle is 30 cm2. Its two sides are 60 cm and 2 cm. Find the angle between these sides.

We apply the formula for the area of a triangle through two sides and the angle between them, which is equal to half the product of the lengths of these sides by the sine of the angle between them.

SаСВ = (АС * ВС * SinАСВ) / 2.

SinACB = 2 * Savs / AC * BC = 2 * 30/2 * 60 = 1/2.

Angle ABC = arcsin (1/2) = 30.

Answer: The angle between the sides of the triangle is 30.



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