The area of one rectangle is 32 cm squared, and the area of the second
| August 6, 2021 | education
The area of one rectangle is 32 cm squared, and the area of the second is 2 times more. What is the perimeter of the second rectangle if all sides of it are equal?
Answer: The perimeter of the second rectangle is 32 cm.
If it is known that the area of the second rectangle is 2 times greater than the area of the first, then it will be:
32 * 2 = 64 cm².
In addition, it is known that the sides of the second rectangle are equal, that is, the length of the side of the rectangle (square) will be determined as the square root of the value of its area:
√64 = 8 cm.
The perimeter is the sum of the lengths of all sides of any polygon. Thus:
8 + 8 + 8 + 8 = 32 cm.
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