The area of one square is 47.6 cm2, and the area of the other is 5.9 cm2 larger

The area of one square is 47.6 cm2, and the area of the other is 5.9 cm2 larger than the area of the first. Find the sum of the areas of two squares.

1). First, we find the area of the second figure given in the condition, knowing that it is 5.9 cm2 larger than the area of the first, we find:

47.6 + 5.9 = 53.5 cm2;

2). Now we can answer the question of the task by adding the areas of both figures, we get:

47.6 + 53.5 = 101.1 cm2.