The area of the axial section is 72 cm²; its generatrix is 2 times the diameter of the base. find the volume of the cylinder.

The axial section of the cylinder is rectangle ABCD.

Let the diameter of the AD circle at the base of the cylinder be equal to X cm, then, by condition, the height of the cylinder AB = 2 * Xcm.

Then Ssec = AD * AB = X * 2 * X = 72 cm2.

2 * X ^ 2 = 72.

X ^ 2 = 36.

X = AD = 6 cm.

AB = 2 * 6 = 12 cm.

The radius of the circle is equal to: AO = AD / 2 = 6/2 = 3 cm.

Determine the area of the base of the cylinder.

Sbn = π * R ^ 2 = π * 9 cm2.

Determine the volume of the cylinder.

V = Sb * h = Sb * AB = π * 9 * 12 = π * 108 cm3.

Answer: The volume of the cylinder is π * 108 cm3.



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