The area of the parallelogram is 20. Point F is the middle of the BC side. Find the area of the trapezoid AFCD.

univerkov | March 1, 2021 | education

From point F, the middle of the segment BC, draw a straight line FE parallel to AB and CD. The FE segment divides parallelogram ABCD into two equal parts SABFE = SEFCD.

SABFE = SABCD / 2 = 20/2 = 10 cm2.

Consider a parallelogram ABFE, in which AF is its diagonal and divides it into two equal triangles.

Then SAFE = SABFE / 2 = 10/2 = 5 cm2.

Trapezium area SAFCD = SEFCD + SAFE = 10 + 5 = 15 cm2.

Answer: The area of the trapezoid AFCD is 15 cm2.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.