The area of the rectangle is 120 cm2. Find the length and width of the rectangle if its width is 5 times less than the length.

Let’s take the length for x and the width of the rectangle for y. 1. Based on the condition, two equations for determining the unknown quantities: 1) x · y = 120, 2) x = y · 5. 2. Substitute the value of x from the 2nd equation in the 1st: 5 y y = 120, y ^ 2 = 120: 5, y ^ 2 = 24, y = v24 cm = v4 6 = 2v6 cm – width .3. Let’s calculate the value of the length x: x = 5 · 2v6 = 10v6 cm. 4. Check: x · y = 10v6 · 2v6 = 20 · 6 = 120 cm ^ 2.
Answer: the length of the rectangle is 10v6 cm, the width is 2v6 cm.