The area of the rectangle is 130 dm2, its length is 130 cm. Find the perimeter of this rectangle.

First of all, we express the width of the rectangle, provided that its area is 130 dm², and the length = 130 cm.
We know that S = a * b. Therefore: b = S: a.

1 dm = 10 cm, so a = 130: 10 = 13 dm.

b = 130: 13 = 10 dm.

The perimeter of such a figure is calculated by the formula:
P = 2a + 2b = 2 * 12 + 2 * 10 = 24 + 20 = 44 dm.



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