The area of the rectangle is 18 a. Find the area of another rectangle, the length of which is 15 times

| February 14, 2021 | education

The area of the rectangle is 18 a. Find the area of another rectangle, the length of which is 15 times less than the length of the given one, and the width is less than 4 times the width.

Let’s denote the length of the first rectangle by a, and the width of the first rectangle by b.

According to the condition of the problem, the area of ​​the first rectangle is 18 m ^ 2, therefore, we can write the following ratio:

a * b = 18.

By the condition of the problem, the length of the second rectangle is 15 times less than the length of the first rectangle, and the width of the second rectangle is 4 times less than the width of the first rectangle, therefore, the length of the second rectangle is a / 15, the width of the second rectangle is b / 4, and the area of ​​the second rectangle is :

a / 15 * b / 4 = a * b / 80 = 18/60 = 0.3 m ^ 2.

Answer: The area of ​​the second rectangle is 0.3 m ^ 2.



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