The area of the rectangle is 20 m2. Find the area of another rectangle, the length of which is 12 times

The area of the rectangle is 20 m2. Find the area of another rectangle, the length of which is 12 times the length of the given one, and the width is 5 times the width of the given one

Let the length and width of the first rectangle be a and b meters, respectively. Then the length and width of the second rectangle, based on the condition, will be equal to (12 * a) meters and (5 * b) meters, respectively. Then the areas of both rectangles are:

S1 = a * b;
S2 = 12 * a * 5 * b = 60 * a * b.

Consequently:

S2 / S1 = (60 * a * b) / (a * b) = 60.

This means that the area of the second rectangle is:

S2 = S1 * 60 = 20 * 60 = 1200 (m 2).

T. to. 1 a = 100 m 2, then:

S2 = 1200 m 2 = 12 a.

Answer: 12 a.