The area of the rectangle is 32 cm by how many times the width of the rectangle is less than its length if the length is 8 cm.

Let’s find a solution to the problem by solving it in two steps.

1. Let’s define in the first action what the width of the rectangle is.

32/8 = 4 centimeters.

2. Find out how many times the width is less than the length.

8/4 = 2 times.

Answer: The width of the rectangle is 2 times less than the length.



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