The area of the rectangle is 32 cm squared, and its perimeter is 24 cm. What can be the lengths of its sides.

Let x cm be long and width y cm.The perimeter is the sum of the lengths of all sides, let’s make the equation:
2 (x + y) = 24
Area is the product of length and width, we will compose the second equation:
x ∗ y = 32
Now let’s put together a system.
2 (x + y) = 24
x ∗ y = 32
We express any variable from one equation and substitute it into another.
x = 32 / y
2 (32 / y-y) = 24
64 / y-y = 24
64-y ^ 2 = 24y
-y ^ 2 + 64-24y = 0
D = 4000
√D = 20
y = 2
find y (Substitute it for the equation).
y = 16