The area of the rectangle is 32 cm2. What is the length and width of a rectangle if the width is 4

The area of the rectangle is 32 cm2. What is the length and width of a rectangle if the width is 4 times shorter than its length?

Let the width of the rectangle be x cm, then the length of the rectangle is 4x cm (if the width is 4 times shorter than the length, then the length, on the contrary, is 4 times longer than the width). By the condition of the problem, it is known that the area of a rectangle (and the area of a rectangle is equal to the product of length and width) is x * 4x cm ^ 2 or 32 cm ^ 2. Let’s make an equation and solve it.

x * 4x = 32;

4x ^ 2 = 32;

x ^ 2 = 32: 4;

x ^ 2 = 8;

x = √8;

x = 2√2 (cm) – width;

4x = 4 * 2√2 = 8√2 (cm) – length.

Answer. Length 8√2 cm, width 2√2 cm.