The area of the rectangle is 32 dm2, the width is 4 dm. Find the length and perimeter of the rectangle.
| March 5, 2021 | education
Given:
The area S of the rectangle is 32 dm2.
The width b of the quadrangle is 4 decimetres.
We calculate the length of this figure by the formula a = S: b:
a = S: b = 32: 4 = 8 decimeters.
Find the perimeter of the polygon by the formula P = a + a + b + b:
P = a + a + b + b = 8 + 8 + 4 + 4 = 24 decimetres.
Answer: the length is 8 decimeters, and the perimeter of the rectangle is 24 decimeters.
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