The area of the rectangle is 32 inches and the width is 4 inches. Find the length and perimeter of the rectangle.

The task:
the area of the rectangle S is 32 dm ^ 2,
width b – 4 dm,
length a -? dm,
perimeter P -? dm.
Decision:
1) calculate the length of the rectangle:
S = a b, a = S: b = 32: 4 = 8 dm;
2) define the perimeter of the rectangle:
P = (a + b) 2 = (8 + 4) 2 = 12 2 = 24 dm.
Answer: the length of the rectangle is a = 8 dm, the perimeter is 24 dm.