The area of the rectangle is 4 times the area of the square. the length of the rectangle is 52 cm. find the width

The area of the rectangle is 4 times the area of the square. the length of the rectangle is 52 cm. find the width of the rectangle if the side of the square is 13 cm. how much is the perimeter of the rectangle?

1) Find the area of ​​the square. The area of ​​a square is equal to the square of its side. S = a ^ 2.

13 ^ 2 = 169 (cm ^ 2).

2) Find the area of ​​the rectangle.

169 * 4 = 676 (cm ^ 2).

3) Find the width of the rectangle. It is necessary to divide the area of ​​the rectangle by its length.

676: 52 = 13 (cm).

4) Find the perimeter of the square. The perimeter of a square is equal to the sum of the lengths of its four sides. P = 4a.

4 * 13 = 52 (cm).

5) Find the perimeter of the rectangle. The perimeter of a rectangle is twice the sum of its length and width. P = 2 (a + b).

2 (13 + 52) = 2 * 65 = 130 (cm).

6) How many centimeters is the perimeter of the rectangle larger than the perimeter of the square?

130 – 52 = 78 (cm).

Answer. The width of the rectangle is 13 cm. The perimeter of the rectangle is 78 cm larger than the perimeter of the square.