The area of the rectangle is 48 m2. what is the length and width of the rectangle if the length is 3 times its width.

Let a rectangle ABCD be given, for which the width AB = x cm, and the length BC = 3 ∙ x cm, since it is known from the condition of the problem that the length of the rectangle is 3 times its width. Then the area of the rectangle will be: S (ABCD) = AB ∙ BC; S (ABCD) = x ∙ 3 ∙ x = 3 ∙ x² (cm²). Knowing that the area of the rectangle is 48 m², we make the equation:

3 ∙ х² = 48;

x² = 48: 3;

x² = 16;

x = √16;

x = 4 (cm) – the width of the rectangle;

3 ∙ 4 = 12 (cm) – the length of the rectangle.

Answer: The length of the rectangle is 12 cm and the width of the rectangle is 4 cm.