The area of the rectangle is 54. Find the perimeter of this rectangle if one of its sides is 6 times larger than the other.

Let x be the width of the rectangle.

Then its length is 6x.

6x * x = 54.

6x ^ 2 = 54.

x ^ 2 = 54: 6.

x ^ 2 = 9.

x = √9.

x = 3 or x = -3.

A value of -3 is not suitable because the side length of a rectangle cannot be expressed as a negative number.

Hence, the width of the rectangle is 3.

Then its length is: 6 x 3 = 18.

Find the perimeter:

(3 + 18) x 2 = 21 x 2 = 42.

Answer: The perimeter is 42.