The area of the rectangle is 616 m2, and its length is 28 m.

The area of the rectangle is 616 m2, and its length is 28 m. Find the area of such a square whose perimeter is equal to the perimeter of the rectangle.

To solve the problem, you first need to find the width of the rectangle.
To do this, its area should be divided by the length of the known side.

616/28 = 22 cm.

After that we find the perimeter of the rectangle.
It will be equal.
2 [28 + 22] 2 * 50 = 100 cm.

If the perimeter of the square is 100 cm, then its side will be equal to a = 100/4.
Divide by 4 since all sides of the square are equal to each other.
a = 25 cm.

To determine the area of a square, you must multiply the two sides.
In this case, we get.

25 * 25 = 625 cm2.

Answer.
The area of the square will be 625 cm2.