The area of the rectangle is 616m2 and its length is 28m. Find the area of a square whose

The area of the rectangle is 616m2 and its length is 28m. Find the area of a square whose perimeter is equal to the perimeter of the rectangle.

1) Find the width of the given rectangle. It is equal to the quotient of dividing its area by length: 616/28 = 22 m;
2) Find the perimeter of the rectangle, it is equal to the sum of the lengths of all sides: 28 * 2 + 22 * 2 = (28 + 22) * 2 = 50 * 2 = 100 m;
3) Find the side of a square whose perimeter is 100 m: 100/4 = 25 m;
4) The area of this square will be 25 * 25 = 625 m2.