The area of the rectangle is 64cm2, and its width is 16cm. Find the side of a square whose perimeter

The area of the rectangle is 64cm2, and its width is 16cm. Find the side of a square whose perimeter is equal to the perimeter of the rectangle.

1. Let’s find how long the rectangle is. If, according to the condition, its area is 64 cm², and the width is 16 cm.

S = ab;

16 * a = 64;

a = 64/16;

a = 4;

Therefore, the length is 4 cm;

2. Find the perimeter of the rectangle:

Pn = 2 (a + b);

Pp = 2 * (16 + 4) = 2 * 20 = 40;

Pp = 40 cm;

3. According to the condition, the perimeter of the rectangle is equal to the perimeter of the square, which means:

Pk = Pp = 40 cm;

4. Find one side of the square:

Pk = 4x;

4x = 40;

x = 40/4;

x = 10;

Therefore, the side of the square is 10 cm.

Answer: the side of the square is 10 cm.