The area of the rectangle is 68dm squared, and the length is 13dm wider than the width. What are the sides of this rectangle?

Let x be the width, then (x + 13) is the length. Then you can write the equation x (x + 13) = 68 x ^ 2 + 13x-68 = 0 D = 13 ^ 2 + 4 * 68 = 169 + 272 = 441 x = (- 13 + √441) / 2 = (- 13 + 21) / 2 = 4 x = (- 13-√441) / 2 = (- 13-21) / 2 = -17 (extraneous root, since X> 0) So 4dm – width 4 + 13 = 17dm – length.
Answer: 17.4