The area of the rectangle is 80 cm2. what will be its area if the width remains unchanged

The area of the rectangle is 80 cm2. what will be its area if the width remains unchanged, and the length is increased by 6 times?

Given:
The area of the original rectangle is 80 cm2.
The second rectangle has the same width as the first.
The length of the second figure is 6 times longer than the length of the first.

The length of the first figure is x centimeters, so the length of the second quadrangle will be 6x centimeters.
Let’s write expressions for the area of each figure, taking the value of y as the width:
x * y = 80;
6x * y = S.
Hence S = 6 * 80 = 480 cm2, that is, the area increases six times.
Answer: the area of the second quadrangle will be 480 cm2.