The area of the rectangle is equal to 120 cm, its length is 7 more than the width, find the perimeter.

Suppose the length of the rectangle is x cm.

Since we know that the length is 7 cm more than the width, its value will be: x – 7 cm.

Since the area is the product of the sides, we get the equation:

x * (x – 7) = 120.

x ^ 2 – 7 * x – 120 = 0.

D ^ 2 = 49 – 4 * 1 * (-120) = 49 + 480 = 529.

D = √529 = 23.

x = (7 + 23) / 2 = 30/2 = 15 cm (length).

x – 7 = 15 – 7 = 8 cm (width).

Find the perimeter of the rectangle.

2 * (15 + 8) = 2 * 23 = 46 cm.

Answer: The perimeter is 46 cm.