The area of the rhombus is 64. One of its diagonals is 2 times larger than the other. Find the smaller diagonal.

univerkov | April 18, 2021 | education

Let the length of the smaller diagonal of the rhombus be X cm, BD = X cm, then, by condition, the length of the larger diagonal is 2 * X cm, AC = 2 * X cm.

The area of a rhombus is half the product of the lengths of its diagonals.

S = AC * BD / 2.

64 = 2 * X * X / 2 = X ^ 2.

X = BD = 8 cm.

Answer: The length of the smaller diagonal of the rhombus is 8 cm.

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