The area of the smaller piston of the hydraulic press is 1 cm2, the area of the larger piston is 200 cm2.

| March 3, 2021 | education

The area of the smaller piston of the hydraulic press is 1 cm2, the area of the larger piston is 200 cm2. A force of 120 N acts on the small piston. What force is obtained on the larger piston of the hydraulic press?

Since the pressure of the fluid in the pistons of the hydraulic press is the same, the following relationship is true:
F1 / S1 = F2 / S2, where F1 is the pressure force on the larger piston, S1 is the surface area of the larger piston (S1 = 200 cm ^ 2 = 200 * 10 ^ -4 m ^ 2), F2 is the pressure force on the smaller piston ( F2 = 120 N), S2 is the surface area of the smaller piston (S2 = 1 cm ^ 2 = 1 * 10 ^ -4 m ^ 2).
Let’s calculate the pressure force on the larger piston:
F1 = F2 * S1 / S2 = 120 * (200 * 10 ^ -4) / (1 * 10 ^ -4) 100 = 24000 N = 24 kN.
Answer: The force of pressure on the larger piston is 24 kN.



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