The area of the smaller piston of the hydraulic press is 2 cm2, and the area of the larger one is 150 cm2.

| July 5, 2021 | education

The area of the smaller piston of the hydraulic press is 2 cm2, and the area of the larger one is 150 cm2. Determine the pressure force acting on the larger piston if a force of 40 N is applied to the smaller piston. To what height will the larger piston rise if the smaller one drops by 30 cm?

Sm = 2 cm2.

Sb = 150 cm2.

Fm = 40 N.

hm = 30 cm.

Fb -?

hb -?

In a hydraulic press, the pressure of a small Pm and a large Pb piston is the same: Pm = Pb.

Let us express the pressure P through the force F, which acts on the piston, and its area S: P = F / S.

Rm = Fm / Sm, Rb = Fb / Sb.

Fm / Sm = Fb / Sb.

Fb = Fm * Sb / Sm.

Fb = 40 N * 150 cm2 / 2 cm2 = 3000 N.

In a hydraulic press, the work of the small Am and the large Ab of the piston is the same: Am = Ab.

Am = Fm * hm.

Ab = Fb * hb.

Fm * hm = Fb * hb.

hb = Fm * hm / Fb.

hb = 40 N * 30 cm / 3000 N = 0.4 cm.

Answer: Fb = 3000 N, hb = 0.4 cm.



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