The arithmetic mean of two numbers 1 of which is 4.6 more than the second is 8.2. Find these numbers.

From the condition we know that the arithmetic mean of two numbers, one of which is 4.6 more than the second is 8.2. In order to find these numbers, we compose and solve a linear equation with one variable.
Let us denote one of the numbers using the variable x, then the second can be written as (x + 4.6).
The arithmetic mean of numbers is equal to the sum of these numbers divided by their number. For two numbers, the formula looks like this:
(a + b) / 2 = m;
(x + x + 4.6) / 2 = 8.2;
2x + 4.6 = 8.2 * 2;
2x + 4.6 = 16.4;
2x = 16.4 – 4.6;
2x = 11.8;
x = 5.9.
The first number is 5.9, and the second is 5.9 + 4.6 = 10.5.