The arithmetic mean of two numbers is 60% of the larger of them.

The arithmetic mean of two numbers is 60% of the larger of them. How many times is the arithmetic mean of these numbers greater than the smaller number?

Given: Numbers A and B, A> B, (A + B) / 2 = 0.6 * A.
Find: ((A + B) / 2): B.
Solution:
(A + B) / 2 = 0.6 * A,
A + B = 1.2 * A,
B = 1.2 * A – A,
B = 0.2 * A.
Thus, we get that (A + B) / 2 = (A + 0.2 A) / 2 = 0.6 * A, therefore
((A + B) / 2): B = 0.6 * A: 0.2 * A = 3.
Answer: 3 times.