The arm ends are acted upon by forces of 8H and 40H. The arm length is 90cm. Where is the fulcrum if the arm is in equilibrium?

x (8H)
90s (40H)
The equation:
8x = 40 (90’s)
8x = 3600-40x
8x + 40x = 3600
48x = 3600
x = 3600: 48
x = 75
90-75 = 15 (cm)
Answer: the fulcrum is 15 cm from a force of 40N



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