The arrow flies vertically upward at a speed of 50 m / s. How high will it rise if its weight is 200g?

Initial data: V0 (speed with which the arrow flew vertically upwards) = 50 m / s; m (boom mass) = 200 g = 0.2 kg.

Reference data: g (acceleration due to gravity) = 10 m / s2.

The height to which the arrow can rise can be calculated using the law of conservation of energy: Ep0 + Ek0 = En + Ek; 0 + Ek0 = En + 0.

m * V0 ^ 2/2 = m * g * h.

h = m * V0 ^ 2 / (2 * m * g) = V0 ^ 2 / 2g.

Let’s make a calculation: h = 50 ^ 2 / (2 * 10) = 125 m.

Answer: The arrow will rise to a height of 125 meters.